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< async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"> 數學的問題!!!!!!!!!!!!!!!!!!!!!!!!!!

發問:

I have a question:Donna has three types of coins: $1 coins , $2 conins and $5 coins.The number of $1 coins is three times that of $2 coins.The number of $2 coins is 5 more than the number of $5 coins.The total value of Donna's coins is $325.How many $2 coins does she have.(Answer in Algebraic... 顯示更多 I have a question: Donna has three types of coins: $1 coins , $2 conins and $5 coins.The number of $1 coins is three times that of $2 coins.The number of $2 coins is 5 more than the number of $5 coins.The total value of Donna's coins is $325.How many $2 coins does she have.(Answer in Algebraic equation)(process and construction)

最佳解答:

Let a be the number of $2 coins. *** number of $1 coins=3a ***number of $2 coins=a ***number of $5 coins=a-5 3a x 1 + 2 x a + 5 (a-5) = 325 3a +2a +5a -25 =325 10a = 350 a= 35 So, the number of $2 coins is 35, the value of $2 coins is 35 x2= $70 So, the number of $1 coins is 35 x3= 105, the value of $1 coins is 105x 1= $105 So, the number of $5 coins is 35-5= 30, the value of $5 coins is 30x 5= $150 $70+ $105+ $150= $325

其他解答:

Let she has x $2 coins Let she has 3x $1 coins Let she has (x-5)$5 coins 2x+1(3x)+5(x-5)=325 2x+3x+5x-25=325 10x=325+25 10x=350 x=35 So she has 35 $2 coins.4E350C6F8B48ECA2