標題:
中二 數學因式分解
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發問:
1) (y+2)^2-(y+2)-12 2) 22/3-1/2ab-a/2b 3)9(p-5)^2-24p(p-5)+16p^2
最佳解答:
1) (y+2)^2-(y+2)-12 =(y+2-4)(y+2+3) =(y-2)(y+5) or (y+2)^2-(y+2)-12 =y^2+4y+4-y-2-12 =y^2+3y-10 =(y-2)(y+5) 2) 22/3-1/2ab-a/2b ??? 3)9(p-5)^2-24p(p-5)+16p^2 =[3(p-5)-4p]^2 ={3p-15-4p)^2 =(p+15)^2 or 9(p-5)^2-24p(p-5)+16p^2 =9(p^2-10p+25)-(24p^2-120p)+16p^2 =(9-24+16)p^2+(-90+120)p+9*25 =p^2+30p+225 =(p+15)^2
其他解答:
魔龍帝齊格益力多 ( 大學級 1 級 ) 第2題解的很棒,佩服佩服^^讚喔|||||(y+2+3)(y+2-4) (y+5)(y-2) ___________________ 22/3-1/2ab-a/2b (-1/6ab)(3a^2-44ab+3) _________________ 9(p-5)^2-24p(p-5)+16p^2 (3(p-5))^2-2(4(p))(3(p-5))+(4p)^2) (3p-15-4p)^2 (-p-15)^2 (p+15)^24E350C6F8B48ECA2
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