標題:
Maths F4...6
發問:
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Question link : http://img8.imageshack.us/img8/7214/001aox.jpg *要解釋/步驟...THX:)* 更新: Question link : http://img8.imageshack.us/img8/7214/001aox.jpg
最佳解答:
22 log_4(3x) - log_4(x - 1) = log_2(3)log(3x)/log4 - log(x - 1)/log4 = log3/log2(1/2)[log(3x)/log2 - log(x - 1)/log2] = log3/log2log(3x/(x - 1)) = log93x = 9(x - 1)x = 3/223(a) 10^x = (2/5)(100^x + 1)xlog10 = log(2/5) + log(100^x + 1)The number one can be omitted and sox = log(2/5) + 2xx = -0.4
其他解答:4E350C6F8B48ECA2
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