標題:
Math Probability statistics
發問:
1) A research scientist reports that mice will live an average of 40 months when their diets are sharply restricted and then enriched with vitamins and proteins. Assuming that the life times of such miceare normally distributed with a standard deviation of 6.3 months, find the probability that a given mouse will... 顯示更多 1) A research scientist reports that mice will live an average of 40 months when their diets are sharply restricted and then enriched with vitamins and proteins. Assuming that the life times of such miceare normally distributed with a standard deviation of 6.3 months, find the probability that a given mouse will live a)more than 32 months; (b)less than 28 months; (c)between 37 and 49 months 2) A soft-drink machine is regulated so that it discharges an average of 200 milliliters per cup. If the amount of drink is normally distributed with a standard deviation equal to 15 milliliters: a)what fraction of the cups will contain more than 224 milliliters? (b)what is the probability that a cup contains between 191 and 209 milliliters? (c)how many cups will probably over flow if 230 milliliter cups are used for the next 1000 drinks? (d)below what value do we get the smallest 25% of the drinks The probability that a patient recovers from a delicate heart operation is 0.9.Of the next 100 patients having this operation, what is the probability that (a)between 84 and 95 inclusive survive? (b)fewer than 86 survive
最佳解答:
此文章來自奇摩知識+如有不便請留言告知
< async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js">
1(a) P(X > 32) = P(Z > (32 - 40)/6.3) = P(Z > -1.2698) = 0.8979 (b) P(X < 28) = P(Z < (28 - 40)/6.3) = P(Z > -1.9048) = 0.0284 (c) P(37 <= X <= 49) = P((37 - 40)/6.3 <= Z <= (49 - 40)/6.3) = P(-0.4762 <= Z <= 1.4286) = 0.6065 2(a) P(X > 224) = P(Z > (224 - 200)/15) = P(Z > 1.6) = 0.0548 (b) P(191 <= X <= 209) = P((191 - 200)/15 < Z < (209 - 200)/15) = P(-0.6 < Z < 0.6) = 0.4515 (c) P(X > 230) = P(Z > (230 - 200)/15) = P(Z > 2) = 0.0228 So, 22 cups will be over flow if 230 milliliter cups are used for the next 1000 drinks (d) 200 - 1.96 * 15 = 170.6 3(a) mean = 90 and standard deviation = sqrt(100 * 0.9 * 0.1) = 3 P(84 <= X <= 95) = P(-5.3333 <= Z <= -3.4444) = 0.0003 (b) P(X < 86) = P(Z < -4.6667) ~ 0
其他解答:4E350C6F8B48ECA2
文章定位：
