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標題:

urgent plzzz

發問:

In 10 tosses of a fair coin, compute the probability of getting 5, 6, 7 or 8 heads.

最佳解答:

Possibility of getting 5 heads =1/2 ^ 10 * 10C5 = 1/1,024 * 252 = 63/256 (0.2461) Possibility of getting 6 heads =1/2 ^ 10 * 10C6 = 1/1,024 * 210 = 105/512 (0.2051) Possibility of getting 7 heads =1/2 ^ 10 * 10C7 = 1/1,024 * 120 = 15/128 (0.1172) Possibility of getting 8 heads =1/2 ^ 10 * 10C8 = 1/1,024 * 45 = 45/1,024 (0.04395) *10C5 means = 10! / [(10-5)! * 5!], the number of possibilities of 5 heads in 10 tosses of a fair coin

其他解答:

5/10 6/10 7/10 8/10A9A3995996B435E3