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< async src="//pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"> 一條數學問題(中一程度)

發問:

*用方程解答* *要步驟* The total age of Mr.Chu and his son is 51. Three years ago, he was 8 times as old as his son. How old is his son now?

最佳解答:

Let x be the age of Mr.chu. x-3=8(51-x-3) x-3=408-8x-24 9x =387 x=43 His son is 51-43=8 years old now.

其他解答:

Set up his son's age is n years old,Mr.Chu is x years old. n+x=51 8(n-3)=x-3 8n-24+3=x 8n-21=x n+8n-21=51 9n=51+21 n=72 over 9 n=8 His son is 8 years old now.|||||x-3=8(51-x-3) x-3=408-8x-24 9x =387 x=43 His son is 8 yaears old|||||中文解釋： 曹先生與他的兒子總歲數是５１歲．３年之後，曹先生比他的兒子大８歲．他的兒子現在多少歲？？？ 設他的兒子現在ｐ歲。 ３年之後姐係曹生同兒子總歲數是５７曹生比佢大８歲姐係曹生３２．５兒子就２４．５歲|||||Let X = Mr Chu's age now, and Y = his son's age now. X + Y = 51 X - 3 = 8 * (Y - 3) X - 3 = 8Y - 24 X = 8Y -24 + 3 X = 8Y - 21 8Y - 21 + Y = 51 9Y = 72 Y = 8 X = 43|||||Let the age of Mr. Chu's son is x, the age of Mr. Chu is 51-x 8(x-3)=51-x-3 8x-24=48-x 9x=72 x=8 The age of his son is 8 nowCF546184A985CA23